1. We need 2n+1 lines in total, to draw 'n' planks in the left side and three lines for EACH of the planks on the right.
The equation to find 'n' is:
2. 2n +1 = 3 X (n-1) since we need 3 lines to represent a plank in the right side.
1. how
2. why 3 times n-1
1. We have taken 'n' as the number of planks in the LHS. Here, only the first plank needs three lines and the following have two more EACH.
1. We need 2n+1 lines in total, to draw 'n' planks in the left side and three lines for EACH of the planks on the right.
The equation to find 'n' is:
2. 2n +1 = 3 X (n-1) since we need 3 lines to represent a plank in the right side.
1. how
2. why 3 times n-1
Thus we need 3 + 2 + 2 and so on to draw in that manner. All the planks after the first need ONLY two lines. So total lines are 2n + 1 OK?
We have one plank LESS on the right hand side. Since the number of planks on LHS is denoted by 'n' the number on the RHS will be (n - 1)
Hope it is clear up to this.
2. We need three lines to denote EACH plank on the RHS. So, we have to multiply the number of planks in RHS by 3 to get the number of lines.
Since the lines drawn are the SAME for planks on LHS and RHS, we equate 2n + 1 and 3 x (n - 1) :thumb:
YES! In fact ONLY for 4 and 3 if drawn in this way! :decision:haha,
only horizontal lines !
also this 4-3 combination is possible only for 4-3 and not for 5-4
I agree with Rajiji,The drawing is wrong!
Check out the lines starting from the left side!
Are you not a math student P J Sir?
It is a very simple calculation.