would that be hypothetical?Yes sir! You have!!
would that be hypothetical?Yes sir! You have!!
Very easy! Make the lady guest sit in the drawing room and enter the kitchen......... How do women manage to hide from other women???:noidea:
WOW! What a nice point to ponder!! :madgrin:When one goes in search of Honey, he must not forget that he gets stung by Bees. .....
I have done a few times to save a :fish2: by the members of this forum.I am recycling/ recirculating my posts. ...........
just for a change of topic and to keep myself as a posting member and keeping in mind the desirability to increase the traffic in this thread, and knowing that many take a random walk in this thread, and any posting can be made with impunity, how about solving this maths quiz?
If a + b + c + d = a x b x c x d
find the value of a, b, c, d
N.B.: 1.decimal places allowed correct upto second digit
2. I do not know the solution (even if there is one!!)
I am sure it will work 0, but will give it some thought
just for a change of topic and to keep myself as a posting member and keeping in mind the desirability to increase the traffic in this thread, and knowing that many take a random walk in this thread, and any posting can be made with impunity, how about solving this maths quiz?
If a + b + c + d = a x b x c x d
find the value of a, b, c, d (for values other than zero)
N.B.: 1.decimal places allowed correct upto second digit
2. I do not know the solution (even if there is one!!)
I am sure it will work 0, but will give it some thought
Let us suppose that
a = 1/ sq.root of 2
b = (-) 1/ sq root of 2.
c = + 2 and
d = (-) 1.
So a+ b+ c+ d = (1/sq root of 2) + (- 1/ sq root of 2) + 2 (- 1) = 1.
a.b.c.d = 1/ sq root of 2 x (- 1/ sq. root of 2) x (2) (-1) =
(- 1/2) x 2 X (-1) = 1.
L.H.S + R.H.S.
Yahooooooooooooooooo!